Question

Find the median if mid value sa 37.5 42.5 47.5 52.5 57.5 and number of students are 30,20,15,13,22 respectively

Answer 1

Given :  mid values       37.5   42.5 47.5 52.5 57.5  

number of students are 30,  20,    15,      13,     22

To Find : Median

Solution:

mid values       37.5   42.5 47.5 52.5 57.5  

Difference between consecutive mid value = 5

5/2 = 2.5

Hence classes   F                 CF

35 - 40               30               30

40 - 45              20                50

45 - 50              15                 65

50 - 55              13                 78

55 - 60              22                100

100/2 = 50  

Hence  45 is the Median

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Answer 2

Step-by-step explanation:

N=390∴

2

N

=

2

390

=195

The cumulative frequency just greater than N/2 i.e.195 is 267 and the corresponding class is 150−160. So, 150−160 is the median class.

∴l=150,f=116,h=10,F=151

Now,

Median =l+

f

2

N

−F

×h

⇒Median=150+

116

195−151

×10=153.80