Find the number of 3digit natural number which are divisible by 6
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102,108......996
a1=102
a2=108
an=996
d=6
an=a+(n-1)*d
996=102+(n-1)*6
996-102=6n-6
894=6n-6
894-6=6n
888/6=n
104=n
therefore there are 104 natural number is divisibal by 6
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