Find the median of first 10 even numbers in process
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Answered by
262
Answer:
First ten even numbers are 2,4,6,8,10,12,14,16,18,20. n is even so, n/2th observation + (n/2+1)2th observation. 10/2th +(10/2+1)th . Then, 5th + 6th/2 = 10+12/2= 11. It is the median.
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5
Step-by-step explanation:
First 10 even numbers are:-
2,4,6,8,10,12,14,16,18,20
N is even so, n/2th observation + (n/2+1)2th observation 10/2th+(10/2+1)th Then, 5th+6th/2=10+12/2=11
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