Find the median of the following data.
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since the given series is in inclusive form.convert
it to exclusive form and preparing cumulative frequency table.we get
now,N=44 (from above table)
N\2=22
now, cumulative frequency just greater than 22 is 25 and the corresponding class is 29.5_39.5
here,L=29.5, h=10, f=9, c.f of preceding class=16 and N\2=22
now, median=l+{h×(N\2)\f
= 29.5+{10×(22-16)\9}
=29.5+{10×6\9}
=29.5+60\9
=29.5+6.6=36.1
hence, median of the data is 36.1
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