Question

Find the median of the following data: weight in kg 15,18,20,23,25,27,28,29 cumulative frequency 6,13,23,37,50,58,61,63

Answer 1

[n/2th + (n/2th+1) term] /2
the median is 24 kg

Answer 2

Answer:

1)  15,18,20,23,25,27,28,29

No. of observations = 8 (even)

So, Median = $\frac{\frac{n}{2}th term+(\frac{n}{2}+1)th term}{2}$

Median = $\frac{\frac{8}{2}th term+(\frac{8}{2}+1)th term}{2}$

Median = $\frac{4th term+5 th term}{2}$

Median = $\frac{23+25}{2}$

Median = 24

2)

Cf      Frequency

6            6

13         13- 6 = 7

23         23 - 13 = 10

37         37-23 = 14

50        50-37 = 13

58        58-50 = 8

61          61-58 = 3

63         63-61 = 2

So  Frequency:  7 ,10 , 14 , 13 , 8  , 3 , 2

n = 7

Median is the mid value

So, mid value is 4th

So, median = 13