find the mid point of ab where a and b are the pts (-5 11) and (7 3) respectively
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Answer:
(1,7)
Step-by-step explanation:
(x1,y1)=(-5,11)
(x2,y2)=(7,3)
(x,y) =(x1+x2/2, y1+y2/2). sectional formula for midpoint.
x= -5+7/2
x=1
y=11+3/2
y=7
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