find the mid term of. -3y^2 +36y +162
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Given: -
34y2 = 2y + 7
On transposing all the terms of the right-hand side to the left-hand side, we get:
-34y2 - 2y - 7 = 0
On comparing this equation with the general form of the quadratic equation ay2 + by + c = 0, we get:
a = -34 , b = -2 and c -7, which are real numbers and a is not equal to zero.
Thus, the given equation is a quadratic equation in the variable y.
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Answer:
Answer is (34)
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