Find the middle term of (2x/3-3y/2)^9
Answers
Answered by
0
Answer:
T5 & T6
Step-by-step explanation:
T5= 9C4 × (2x/3)^5 × (-3y/2)^4
T6= 9C5 × (2x/3)^3 × (-3y/2)^6
Similar questions