find the middle term of sequence formed by all three digit numbers which leave a remainder 5 when divided by 7. also find sum of all numbers on both side of middle term separately
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AP be... 103,110,.........,999
an=999
103+7n-7=999
7n=903
n=129
middle term=(139+1)/2=70
a70= 103+69×7=586
now
AP(2)=103,110,.....586
AP(3)=586,.........,999
now u can find the sum
an=999
103+7n-7=999
7n=903
n=129
middle term=(139+1)/2=70
a70= 103+69×7=586
now
AP(2)=103,110,.....586
AP(3)=586,.........,999
now u can find the sum
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Which class question ???
10 or 11 which ???
May you tell me please Sir ???
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