Find the middle term of the sequence formed by all numbers between 9 and 95 leaving a remainder of 1 when divided by 3 also find the sum of the numbers on both sides of the middle term separate;y
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Hey !!!!!!
Well Well Well it's a question similar to the one given in the optional exercise of NCERT. No worry I'll solve it.
First let's make the sequence
10 , 13 , 16 , ... 94
Here,
a = 10
d = 3
l = 94
n = ?
Therefore, l = a + (n - 1) d
=> 94 = 10 + (n - 1 )3
=>( n - 1)3 = 84
=> n - 1 = 28
Here middle term = median
Median = { (n + 1)/2 }th observation
=> { (29 + 1)/2 }th observation
=> { 30/2 }th observation
=> { 15 }th observation
=> a15
We know a15 = a + 14d
= 10 + 14(3)
= 10 + 42
= 52
Thus the middle term is 52.
Well Well Well it's a question similar to the one given in the optional exercise of NCERT. No worry I'll solve it.
First let's make the sequence
10 , 13 , 16 , ... 94
Here,
a = 10
d = 3
l = 94
n = ?
Therefore, l = a + (n - 1) d
=> 94 = 10 + (n - 1 )3
=>( n - 1)3 = 84
=> n - 1 = 28
Here middle term = median
Median = { (n + 1)/2 }th observation
=> { (29 + 1)/2 }th observation
=> { 30/2 }th observation
=> { 15 }th observation
=> a15
We know a15 = a + 14d
= 10 + 14(3)
= 10 + 42
= 52
Thus the middle term is 52.
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