Find the middle term of the sequence formed by all three digit numbers which leaves a remainder 5 when divided by 7.Also,find the sum of all numbers on both sides of middle terms separately.
Answers
Answered by
1
I don't know broooooooooo
Answered by
3
Answer:
the sequence is 103,110.........,999
therefore 999=103+(n-1)7
n=129
therefore 129+1/2=65th term is the middle term
middle term= 103+64(7)=551
sum of first 64 terms=32{206+63(7)}
=20704
sum of last 64 terms= 32{1116+63(7)}
= 49824
Similar questions