Find the middle term of the sequence formed by all three digit number
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Answer: 549 and 550
Step-by-step explanation:
The sequence is 100, 101, 102, ....., 999
This is an AP with first term, a=100 ; common difference, d=1 and nth term aₙ=999. First we will find n.
aₙ=999 ⇒ a+(n-1)d=999
⇒100+(n-1)1=999
⇒n=900
so there are 900 3 digit numbers. So there are two middle numbers which are 450 th number anf 451st no
a₄₅₀=100+449x1=549
a₄₅₁=550
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