Math, asked by moni8533, 10 months ago

Find the middle term of the sequence formed by all three digit number

Answers

Answered by shameemamk
0

Answer: 549 and 550

Step-by-step explanation:

The sequence is 100, 101, 102, ....., 999

This is an AP with first term, a=100 ; common difference, d=1 and nth term aₙ=999. First we will find n.

aₙ=999 ⇒ a+(n-1)d=999

⇒100+(n-1)1=999

⇒n=900

so there are 900 3 digit numbers. So there are two middle numbers which are 450 th number anf 451st no

a₄₅₀=100+449x1=549

a₄₅₁=550

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