Question

find the midpoint of the
line
segment joining (2,8
a (6,-7)​

Answer 1

Answer:

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

Step-by-step explanation:

$let , \: the \: mid-point \: joining \\ \: the \: line \: segment \: be \: P(x,y).$

$Here , \: x1 = 2 \: \: \: , y1 = 8$

$and, /: x2 = 6 \: \: \: \: \: \: , y2 = -7$

$By \: mid - point \: formula \: , we \: get :$

$X = \frac{x1+x2}{2}$

$=> X = \frac{2 + 6}{2}$

$= \frac{8}{2} = 4$

$Now, \: Y = \frac{y1+y2}{2}$

$=> Y = \frac{8+(-7)}{2}$

$= \frac{8 - 7}{2} = \frac{1}{2}$

$therefore , \: the \: mid-point \\ \: of \: the \: line \: \\ segment \: joining \: the \: \\ points \: is \: (4, \: \frac{1}{2} ).$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

$\star \: i \: hope \: you \: will \: understand \: me\star$

Answer 2

Step-by-step explanation:

let,themid−pointjoining

thelinesegmentbeP(x,y).

Here , \: x1 = 2 \: \: \: , y1 = 8Here,x1=2,y1=8

and, /: x2 = 6 \: \: \: \: \: \: , y2 = -7and,/:x2=6,y2=−7

By \: mid - point \: formula \: , we \: get :Bymid−pointformula,weget:

X = \frac{x1+x2}{2}X=

2

x1+x2

= > X = \frac{2 + 6}{2}=>X=

2

2+6

= \frac{8}{2} = 4=

2

8

=4

Now, \: Y = \frac{y1+y2}{2}Now,Y=

2

y1+y2

= > Y = \frac{8+(-7)}{2}=>Y=

2

8+(−7)

= \frac{8 - 7}{2} = \frac{1}{2}=

2

8−7

=

2

1

\begin{gathered}therefore , \: the \: mid-point \\ \: of \: the \: line \: \\ segment \: joining \: the \: \\ points \: is \: (4, \: \frac{1}{2} ).\end{gathered}

therefore,themid−point

oftheline

segmentjoiningthe

pointsis(4,

2

1

).

\begin{gathered}please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))\end{gathered}

pleaselikemyanswer

&

markmebrainliestplease:)))

\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star⋆

PLEASE

F

OLLOW

let,themid−pointjoining

thelinesegmentbeP(x,y).

Here , \: x1 = 2 \: \: \: , y1 = 8Here,x1=2,y1=8

and, /: x2 = 6 \: \: \: \: \: \: , y2 = -7and,/:x2=6,y2=−7

By \: mid - point \: formula \: , we \: get :Bymid−pointformula,weget:

X = \frac{x1+x2}{2}X=

2

x1+x2

= > X = \frac{2 + 6}{2}=>X=

2

2+6

= \frac{8}{2} = 4=

2

8

=4

Now, \: Y = \frac{y1+y2}{2}Now,Y=

2

y1+y2

= > Y = \frac{8+(-7)}{2}=>Y=

2

8+(−7)

= \frac{8 - 7}{2} = \frac{1}{2}=

2

8−7

=

2

1

\begin{gathered}therefore , \: the \: mid-point \\ \: of \: the \: line \: \\ segment \: joining \: the \: \\ points \: is \: (4, \: \frac{1}{2} ).\end{gathered}

therefore,themid−point

oftheline

segmentjoiningthe

pointsis(4,

2

1

).

\begin{gathered}please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))\end{gathered}

pleaselikemyanswer

&

markmebrainliestplease:)))

\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star⋆