Question

Find the minimum and maximum value of 3cos x + 4 sinx +8

Answer 1

min.-4<br /> max.-12<br />(3cosx=(-3,3)<br />4sinx=(-4,4))<br />find common and add 8 to both limits<br /> common between is (-4,4) therefore now, (-4+8,4+8)=(4,12)