Find the minimum energy a photon must have to create an electron-positron pair in the presence of a stationary nucleus of mass M.
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Answer:
2mc^2(1+m/M)
Explanation:
We know that mass of stationary nucleus is 2mc^2(1+m/M)
Here c is the light speed and m mass of electron in rest
The total energy in the system would be the sum of all rest energy and kinetic energy.
It can be written as;
˙M=((2m+M)c^2+KE)^2
The expression for the minimum energy a photon must have is given by,
Now the minimum energy a photon should posses to create an electron positron pair, should be greater than
Minimum energy > 2mc^2(1+m/M)
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