Question

find the minimum value of 2x^2-7x-4=0​

Answer 1

Step-by-step explanation:

The minimum value of ax

2

+bx+c if a>0 is

2a

4ac−b

2

Hence the minimum value of x

2

−12x+40 is

2(1)

4(40)(1)−(12)

2

=8

The maximum value of ax

2

+bx+c if a<0 is

2a

4ac−b

2

Hence the maximum value of −9x

2

+24x+8 is

2(−9)

4(8)(−9)−(24)

2

=16