Question

find the minimum value of 5sinx+12cosx​

Answer 1

Answer:

ans. minimum value of x is 0°

= so,

= 5 ×sinx+12cosx

=5×sin0°+12cos0°

=5×0+12×1

=0+12=12

hence,minimum value is 12

hope my answer help u

Answer 2

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Ans:-

minimum value of x is 0°

= so,

= 5 ×sinx+12cosx

=5×sin0°+12cos0°

=5×0+12×1

=0+12=12

Hence,minimum value is 12