Find the minimum value of the function f(x) = x2 6x +8
Answers
Answer:
- 1
Step-by-step explanation:
Given---> f ( x ) = x² + 6x + 8
To find ---> Minimum value of given function
Solution---> ATQ,
f ( x ) = x² + 6 x + 8
We form whole square here,
f ( x ) = x² + 6 x + 8
We can write 6 as 3 × 2 .
= x² + 2 ( 3 ) ( x ) + 8
= x² + 2 ( 3 ) ( x ) + 8 + 1 - 1
= { x² + 2 ( 3 ) ( x ) + 9 } - 1
= ( x + 3 )² - 1
So for mininimum value of f ( x ) ,
x + 3 = 0
=> x = - 3
Now , minimum value of f ( x ) is
= ( 0 )² - 1
= 0 - 1 = - 1
Step-by-step explanation:
Answer
Given---> f ( x ) = x² + 6x + 8
To find ---> Minimum value of given function
Solution---> ATQ,
f ( x ) = x² + 6 x + 8
We form whole square here,
f ( x ) = x² + 6 x + 8
We can write 6 as 3 × 2 .
= x² + 2 ( 3 ) ( x ) + 8
= x² + 2 ( 3 ) ( x ) + 8 + 1 - 1
= { x² + 2 ( 3 ) ( x ) + 9 } - 1
= ( x + 3 )² - 1
So for mininimum value of f ( x ) ,
x + 3 = 0
=> x = - 3
Now , minimum value of f ( x ) is
= ( 0 )² - = 0 - 1 = - 1