Math, asked by vedunalwale, 5 months ago

Find the minium value of if y= 4-4x-4x^2​

Answers

Answered by rakshith0806
0

Step-by-step explanation:

y=4-4x-4x^2 ; dy/dx= -4-8x; at dy/dx=0 ,y attains minimum value ; -4-8x=0 ; x= -1/2

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