Question

find the missing angle of a triangle. Pls click the Pic to view the full Pic. Pls answer this question in detailed steps
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Answer 1

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∠BAC = 61°

∠ABC = 107°

∠ACB = 12°

Step-by-step explanation:

GivEn:

• ∠BAC = (3x + 28)°
• ∠ABC = (5x + 52)°
• ∠ACB = ( 2x - 10)°

To finD:

• Measures of all angles of this triangle

Solution:

As we know that according to Angle sum property of triangle, Sum of all angles of triangle is 180°.

According to Angle sum property of triangle:

(3x+28)°+(5x+52)°+(2x-10)° = 180°

=> (10x+70)° = 180°

=> 10x = 180° - 70°

=> 10x = 110°

=> x = $\small{\bf{\frac{110}{10} }}$

=> x = 11

Now, measures of angles are :

• (3x + 28)° => (3×11+ 28)° => (33+28)° = 61°
• (5x + 52)° => (5×11+52)° => (55+52)° = 107°
• ( 2x - 10)° => (2×11 -10)° => (22-10)° = 12°

Answer 2

Answer:

$\huge \mathfrak \orange {solution}$

∠BAC = 61°

∠ABC = 107°

∠ACB = 12°

Step-by-step explanation:

GivEn:

∠BAC = (3x + 28)°

∠ABC = (5x + 52)°

∠ACB = ( 2x - 10)°

To finD:

Measures of all angles of this triangle

Solution:

As we know that according to Angle sum property of triangle, Sum of all angles of triangle is 180°.

According to Angle sum property of triangle:

(3x+28)°+(5x+52)°+(2x-10)° = 180°

=> (10x+70)° = 180°

=> 10x = 180° - 70°

=> 10x = 110°

=> x = 100/10

=> x = 11

Now, measures of angles are :

(3x + 28)° => (3×11+ 28)° => (33+28)° = 61°

(5x + 52)° => (5×11+52)° => (55+52)° = 107°

( 2x - 10)° => (2×11 -10)° => (22-10)° = 12°