Math, asked by Kommii4824, 11 months ago

Find the missing frequencies in the following frequency distribution if it is known that the mean of the distribution is 50.

Answers

Answered by nikitasingh79
5

Given frequency distribution :

x :

10  30  50  70  90

f:

17  f1  32  f2  19

Total 120

Solution :

From the table :

Σfixi = 3480 + 30f1 + 70f2  , Σfi = 68 + f1 + f2

Given : Σfi = 120 , Mean = 50

Σfi = 68 + f1 + f2

120 = 68 + f1 + f2

f1 + f2 = 120 - 68

f1 + f2 = 52  

f1 = 52 - f2 ………….(1)  

MEAN = Σfixi / Σfi

50 = (3480 + 30f1 + 70f2) /120

50 × 120 = (3480 + 30f1 + 70f2)

6000 = 3480 + 30f1 + 70f2

6000 - 3480 = 30f1 + 70f2

2520 = 30f1 + 70f2

30f1 + 70f2 = 2520

10 ( 3f1 + 7f2) = 2520

3f1 + 7f2 = 2520/10

3f1 + 7f2 = 252 ……………(2)

3(52 - f2) + 7f2 = 252  

[From eq 1]

156 - 3f2 + 7f2 = 252

156 + 4f2 = 252  

4f2 = 252 - 156  

4f2 = 96

f2 = 96/4

f2 = 24

Putting this value of f2 in eq 1  

f1 = 52 - f2

f1 = 52 - 24

f1 = 28  

Hence, the value of f1 is 28 & f2 is 24 .

HOPE THIS ANSWER WILL HELP YOU….

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Answered by jungkook1997
0

Step-by-step explanation:

here is your answer

X=28 and y=24

Attachments:
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