Question

Find the missing measurement using a proportion.
A photo is 15 centimeters high and 9 centimeters wide. Mikael wants to proportionately shrink it so its height is 6 centimeters high. How wide would it then be?

Answer 1

Given : A photo is 15 centimeters high and 9 centimeters wide.

Mikael wants to proportionately shrink it so its height is 6 centimeters high.

To Find : How wide would it then be

Solution :

Photo Original height  = 15 cm

Photo Original width  = 9 cm

Shrinked height  = 6 cm

Shrinked width =  w  cm

Original height  / Shrinked height   =  Original width  / Shrinked width

=>   15/ 6    = 9/w

=> 5/2   = 9/w

=> w = 9 * 2/5

=> w = 18/5

=> w = 3.6

it would be 3.6 cm wide

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Answer 2

$\huge \cal \mid \fcolorbox{blu}{lime}{ ANSWER } \mid$

$\tt \: Original \: height \: = 15cm \\ \tt \: Original \: width \: = 9cm \: \: \: \:$

$\tt Shrinked \: height \: = 6cm \: \: \: \: \: \: \: \: \: \\ \tt \: Shrinked \: width \: = let \: it \: be \cal \: x$

$\tt \: So -:$

$\tt \: \frac{original \: height}{shrinked \: height} = \frac{original \: width}{shrinked \: width}$

$\tt \: \frac{15}{2} = \frac{9}{ \cal x}$

$\tt \: \frac{5}{2} = \frac{9}{ \cal x}$

$\cal \: x \tt \: = 9 \times \frac{2}{5}$

$\cal \: x \: = \tt \: \frac{18}{5}$

$\cal \: x = \tt \: 3.6$

$\tt \color{green}Answer \: = 3.6$