find the missing number 3 4 12 7 32, 1 5 11 8 56, 2 9 6 3 x
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Answered by
123
It is very easy.
First of all subtract the numbers horizontally and then find the product of their differences.
Don't be bothered of negative sign, you've to concerned with mod of the difference.
Let say for the first case: (12 - 4) x (7 - 3) = 8 x 4 = 32. (i.e. the number at the centre.)
Similarly for the second case: (11 - 5) x (8 - 1) = 6 x 7 = 42.
Finally for the third case: (9 - 6) x (3 - 2) = 3 x 1 = 3 (Ans)
ragnarmonk:
The options are wrong ,I have read same question in RS agarwal ,the answer should be 31.
@ragnarmonk can you tell me the logic for your answer?
bahi questionkya hoocha hai aur and kya dai rahai ho 42=56 hai
Answered by
133
Answer:
4+12+3+7=26=2+6=8=8*4=32
5+11+1+8=25 =2+5 =7=7×8=56
9+6+2+3=20=2+0=2=2*12=24 ans.....
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