find the missing tearm.
____,38____,_____,______,-22
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Given: a
2 =38, and a 6 =−22
We know that,
a n =a+(n−1)d
a 2 =a+(2−1)d
38=a+d....(i)
and a 6 =a+(6−1)d−22=a+5d....(ii)
Solving linear equation (i) and (ii), we get
a+d−a−5d=38−(−22)
⇒−4d=60
⇒d=−15
Putting the value of d in equation (i), we get
a+(−15)=38
a−15=38
⇒a=53
Now,a
3=a+2d=53+2(−15)=53−30=23
a
4=a+3d=53+3(−15)=53−45=8
a
5 =a+4d=7+4(−15)=53−60=−7
Hence, the missing terms are 53,23,8 and −7
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