Question

Find the modules & argument of complex number z=-1-iroot3

Answer 1

Answer:

z=–1–root 3

complex number z is of the form

x+iy

Here x=‐1 y=–root 3

Modulus of z = [z]

=root x^2+y^2

=root (–1)^2+(–root 3)^2

=root 1+3

=root 4

=2

Mark me as brainliest and follow me or like please