Question

find the molality of 15percent of H2SO4.
density =1.020. also find the molarity​

Answer 1

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Answer 2

M = $\dfrac{W_B}{M_B×V_L}$

Molecular weight of H2SO4=2×1+32+64

⇒98gmol−1

M=15g×100098g/mol×115g×1.02g/cm3

=1500011495.4 molar

=1.3048 molar

m (molality) =WB×1000WB×100g

⇒15g×1098gmol−1

⇒15098

⇒1.53 molal