Question

find the molality of the solution obtained whan 63 gram HNO3 is dissolved in 750 gram water

Answer 1

Moles of HNO₃ = 63 g / (63 g/mol) = 1 mol
Weight of solvent = 750 g = 0.75 kg

Molality = Moles of solute / Weight of Solvent in kg
= 1 mol / (0.75 kg)
= 1.33 molal

Molality of solution is 1.33 molal

Answer 2

Hi Himanshupaandey!!

here's the answer to your question:

We all know that Molality = Moles of solute / Weight of Solvent in kg
In the question, it is given that:
*Moles of HNO₃ = 1 mol
*Weight of solvent ( in kg) = 750/1000 kg = 0.75 kg
= 1 mol / (0.75 kg)
= 1.33 molal

Therefore, Molality of solution is 1.33 molal


Hope that answer helps!!
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