Find the zeros of quadritic polynomials and verify tbe relationship between the zeroes and the coefficients.(x2-2x-8)
Answers
Answered by
5
X^2-2x-8=0
=> x^2-4x+2x-8=0
=> x(x-4)+2(x-4)=0
=> (x-4)(x+2)
Zeros of polynomial are 4 and -2.
Compare given equation with standard equation ax^2+bx+c=0
We will get a=1,b=-2,c=-8
Relationship between zero's: sum of zero's= -b/a
=> -2+4= -(-2)/1
=> 2=2
Now product of zero's= c/a
=> -2*4= -8/1
=> -8=-8
Similar questions