Question

find the molarity of 0.98 of H2SO4 of volume 500 ml. (class 11th)​

Answer 1

Answer:

Normality=no. of gram equivalents /vol of solution in L

=mass×1000/equivalent wt × vol of sol(ml)

=9.8×1000/49×500

= 0.4 eq/l

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

We are given:

Given mass of sulfuric acid = 9.8 g

Equivalent mass of sulfuric acid =  

Volume of solution = 500 mL

Putting values in above equation, we get: