Find the molarity of 10% weight by weight aqueous solution of H2SO4 if density of solution is 1.1gm/ml
Answers
Answer:
Given :-
Mass = ?
% Concentration = 10 % => 0.1
Density = 1.1 g/ml
Volume = 1000 ml
ON PUTTING VALUE :-
\large\implies{\sf 0.1 \times 1.1 \times 1000}⟹0.1×1.1×1000
\large{\boxed{\sf Mass= 110 g}}
Mass=110g
\large{\sf In\:1L\:We\:Have\:110g}In1LWeHave110g
\large{\boxed{\sf Mole(n)={\frac{Mass}{Molecular\:Weight}}}}
Mole(n)=
MolecularWeight
Mass
We have calculated
Mass (m) = 110g
Molar mass of \sf{H_{2}SO_{4}}H
2
SO
4
= \sf{ 2+32+16 \times 4}2+32+16×4
\large{\sf Molecular\:Weight (M_{wt}) = 98}MolecularWeight(M
wt
)=98
\large{\sf n ={\frac{110}{98}}}n=
98
110
\large{\boxed{\sf n=1.12}}
n=1.12
WE HAVE TO FIND MOLARITY :-
FORMULA TO FIND MOLARITY (M) IS :-
\large{\boxed{\sf M ={\frac{Mole\:Of\:Solute}{Litre\:Of\:Solute}}}}
M=
LitreOfSolute
MoleOfSolute
\large{\sf M = {\frac{1.12}{1}}}M=
1
1.12
\large{\boxed{\sf M = 1.12 Mol/litre}}
M=1.12Mol/litre
Explanation:
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