Find the molarity of 5m molal naoh solution having density 1.5 g ml
Answers
Mass of 5 NaOH moles = 5x40g = 200g
Mass of solution = Mass of solute + Mass of solvent
Mass of solution = 1000g + 200g = 1200g
Volume of solution = Mass of solution / Density of Solution
Volume of solution = 1200g / 1.5g ml
Volume of solution = 1200/1.5
Volume of solution = 800ml
Molarity = No. of moles / Volume of solution in litre
Molarity = 5 / 0.800L
Molarity = 1/0.160L
Molarity = 6.25M
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Answer:
5 molal solution means 5 mole of solute in 1000 gram of solvent
Mass of 5 NaOH moles = 5x40g = 200g
Mass of solution = Mass of solute + Mass of solvent
Mass of solution = 1000g + 200g = 1200g
Volume of solution = Mass of solution / Density of Solution
Volume of solution = 1200g / 1.5g ml
Volume of solution = 1200/1.5
Volume of solution = 800ml
Molarity = No. of moles / Volume of solution in litre
Molarity = 5 / 0.800L
Molarity = 1/0.160L
Molarity = 6.25M
Explanation:
5 molal solution means 5 mole of solute in 1000 gram of solvent
Mass of 5 NaOH moles = 5x40g = 200g
Mass of solution = Mass of solute + Mass of solvent
Mass of solution = 1000g + 200g = 1200g
Volume of solution = Mass of solution / Density of Solution
Volume of solution = 1200g / 1.5g ml
Volume of solution = 1200/1.5
Volume of solution = 800ml
Molarity = No. of moles / Volume of solution in litre
Molarity = 5 / 0.800L
Molarity = 1/0.160L
Molarity = 6.25M