Question

);Find the moment of 25kN force about point 'P'.​

Answer 1

Answer:

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Solution:

Force applied = 25 N

\bot⊥ distance from the point of rotation = ?

Moment of force = Force \times× \bot⊥ distance

2.5 = 25 \times× \bot⊥ distance

distance = 2.5/25 = 1/10 m = 10 cm