Question

. Find the moment of force of 20 N about an axis of rotation at distance 0.5 m from
the force.​

Answer 1

Answer

Given :-

Force - 20N

Distance - 0.5m

Now,

Moment of force = Force × perpendicular distance

= 20×0.5

= 10Nm

Hope it will help you

Answer 2

Given :-

Force applied = 20 N

Perpendicular distance from the axis of rotation = 0.5 m

To Find :-

The momentum of force.

Analysis :-

Here we are given with the force and the perpendicular distance.

In order to find the momentum of force substitute the values given in the question such that momentum of force is equal to force multiplied by perpendicular distance.

Solution :-

We know that,

• f = Force
• s = Displacement

Using the formula,

$\underline{\boxed{\sf Momentum \ of \ force=Force \times Displacement }}$

Given that,

Force (f) = 20 N

Displacement (s) = 0.5 m

Substituting their values,

⇒ 20 × 0.5

⇒ 10 Nm

Therefore, the momentum of force is 10 Nm.