Question

Observe the following sets of quantum numbers for a given orbital.
n=4,1= 2, m=0
The CORRECT orbital is
(1) 3d 2 –y2
(2) 4px
(3) 4dz2
(4) 4s​

Answer 1

Answer:

I think the last one

Explanation:

it may be incorrect

Answer 2

The correct orbital is 4dz². (The correct option is 3)

• We have been given n = 4 → implies that the central electronic shell or the principal quantum number is 4. Hence, the electron is in the 4th shell.
• The angular quantum number l = 2 → implies that the subshell is 'd'. It describes the shape of the orbital. (l = 0 → 's' subshell, l = 1 → 'p' subshell, l = 2 → 'd' subshell & l = 3 → 'f' subshell)
• We also know that the magnetic quantum number, m = 0, which means the electron is present in dz². It denotes the spatial arrangement of an orbital.
• In conclusion, we can say that the electron is present in the 4dz² orbital.

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