Question

Find the moment of inertia of an hydrogen molecule about an axis passing through its centre of mass and perpendicular to the internuclear axis.Given mass of hydrogen atom = 1.7 *10^-27 kg , inter atomic distance = 4* 10^-10.

Answer 1

Hey dear,

◆ Answer - 1.36×10^-46 kgm^2

◆ Explanation-
# Given-
m = 1.7×10-27 kg
r = 4×10^-10 m

# Solution-
Here,
Total mass M = 2m
Radius of rotation R = r/2

Moment of inertia of hydrogen molecule is given by-
M.I. = MR^2
M.I. = (2m)(r/2)^2
M.I. = mr^2/2
M.I. = 1.7×10-27 × (4×10^-10)^2 / 2
M.I. = 1.36×10^-46 kgm^2

Hope this is useful...

Answer 2

Rotational kinetic energy can be expressed as: Erotational=12Iω2 E rotational = 1 2 I ω 2 where ω is the angular velocity and I is the moment of inertia around the axis of rotation.