Question

Find the moment of inertia of the hydrogen molecule of mass 1.7

Answer 1

find the moment of inertia of an hydrogen molecule about an axis passing through its centre of mass and perpendicular to the internuclear axis.Given
mass of hydrogen atom = 1.7 *10^-27 kg , inter atomic distance = 4* 10^-10.


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Answer 2

# Given-

m = 1.7×10-27 kg

r = 4×10^-10 m

# Solution-

Here,

Total mass M = 2m

Radius of rotation R = r/2

Moment of inertia of hydrogen molecule is given by-

M.I. = MR^2

M.I. = (2m)(r/2)^2

M.I. = mr^2/2

M.I. = 1.7×10-27 × (4×10^-10)^2 / 2

M.I. = 1.36×10^-46 kgm^2