Question

A train leaves from a station and moves at a certain speed. after 2 hours, another train leaves from the same station and moves in the same direction at a speed of 60 mph. if it catches up with the first train in 4 hours, what is the speed of the first train?

Answer 1

Let the speed of the first train be ‘s’.

Distance covered by the first train in (2+4) hours = Distance covered by second train in 4 hours

Therefore, 6s = 60*4

Solving which gives s=40.

So the slower train is moving at the rate of 40 mph.