Math, asked by rasinh9parmila, 1 year ago

Find the multiplicative inverse of (6+5i) 2

Answers

Answered by MaheswariS
21

\textbf{Given:}

(6+5i)^2

\textbf{To find: Multiplicative inverse of $(6+5i)^2$}

(6+5i)^2

=6^2+(5i)^2+60\;i

=36-25+60\;i

=11+60\;i

\text{Now,}

\text{Multiplicative inverse of $(6+5i)^2$}

=\displaystyle\frac{1}{(6+5i)^2}

=\displaystyle\frac{1}{11+60i}

\text{Multiply both numerator and}\;\;\;\;\text{denominator by 11-60i}

=\displaystyle\frac{1}{11+60i}{\times}\frac{11-60i}{11-60i}

=\displaystyle\frac{11-60i}{(11)^2-(60i)^2}

=\displaystyle\frac{11-60i}{121+3600}

=\displaystyle\frac{11-60i}{3721}

\therefore\textbf{The multiplicative inverse of $\bf(6+5i)^2$ is $\bf\displaystyle\frac{11-60i}{3721}$}

Find more:

If a-bi/a+bi=1+i/1-i then,prove a+b=0

https://brainly.in/question/14173316

Express the complex number z = 5+i/2+3i in the form a + ib

https://brainly.in/question/6695271

Answered by Umangbisht
7

Answer:

Step-by-step explanation:

Attachments:
Similar questions