Question

Find the natural no.s between 101 and 999 which are divisible by both 2 and 3

Answer 1

The number divisible by both 2 and 3 will divisible by 6

102,108---------------------------996
a=102,l=996,d=6
l=a+(n-1)d
996=102+(n-1)6
996-102=(n-1)6
894/6=n-1
149=n-1
149+1=n
n=150

Answer 2

n= 150 this is a perfect answer