Question

find the natural numbers between 95and 985 which are divisible by 2 and 5 both​

Answer 1

Ive attached the answer below

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Answer 2

The total number of terms(n) = 89

Step-by-step explanation:

The natural numbers  between 95 and 985, divided by 2 and 5 both (divisible by 10):

100, 110, 120, .....,980

To find, the total number of terms(n)=?

Here, first term(a) = 100, common difference(d) = 110 - 100 = 10 and

last term ($a_{n}$) = 980

We know that,

The nth term of an AP,

$a_{n}$ = a + (n - 1)d

⇒ 100 + (n -1)10 = 980

⇒  (n -1)10 = 980 - 100 = 880

⇒  $n-1=\dfrac{880}{10}=88$

⇒ n = 88 + 1 = 89

Hence, the total number of terms(n) = 89