Question

Find the nature of root of the quadratic equation 2 x square - 4 x + 3=0​

Answer 1

$2 {x}^{2} - 4x + 3 = 0 \\ a = 2 \: \: \: b = - 4 \: \: \: c = 3 \\ {b}^{2} - 4ac \: = { - 4}^{2} - 4(2)(3) \\ = 16 - 24 \\ = - 8 \: < 0$

Therefore, The roots are not real.

Answer 2

Answer:

Hence, it is not real roots

Step-by-step explanation:-

★ Concept :

• The quadratic equation in standard form, ax² + bx + c = 0. Identify the values of a, b, c.

D < 0 , no real roots

D = O , two equal real roots

D > O , Two district real root

★ Solution :

Given Quadratic equation

➙ 2 x² - 4 x + 3 = 0

➙ a = 2, b = -4 , c = 3

➙ D = b² - 4 a c

➙ ( - 4 ) ² - 4 × 2 × 2

➙ 16 - 24 = - 8 < 0

➙ D < 0

★ Hence, it is not real roots