Question

find the nature of roots 2 x square minus 4x minus 7

Answer 1

hey mate!!!!!!

Answer:

REAL ROOTS

Step-by-step explanation:

D = b^2 - 4ac

D = -4 ^2 - 4*2*-7

D = 16 + 56

D  = 72

hope it helps!!

Answer 2

Root 2x^2 - 4x - 7

D = b^2 - 4ac

= (- 4)^2 - 4 ×2 × (-7)

= 16 +56

= 72

Therefore D > 0

So, roots is real