find the nature of roots: 4x2-7x+3=0
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Step-by-step explanation:
The roots of 4x^2 + 7x + 3 = 0 have to be determined using factorization.
4x^2 + 7x + 3 = 0
=> 4x^2 + 4x + 3x + 3 = 0
=> 4x(x + 1) + 3(x + 1) = 0
=> (4x + 3)(x + 1) = 0
(4x + 3) = 0
=> x = -3/4
(x + 1) = 0
=> x = -1
The roots of the equation are x = -1 and x = -3/4
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Answered by
0
Answer:
Step-by-step explanation:
The roots of 4x^2 + 7x + 3 = 0 have to be determined using factorization.
4x^2 + 7x + 3 = 0
=> 4x^2 + 4x + 3x + 3 = 0
=> 4x(x + 1) + 3(x + 1) = 0
=> (4x + 3)(x + 1) = 0
(4x + 3) = 0
=> x = -3/4
(x + 1) = 0
=> x = -1
The roots of the equation are x = -1 and x = -3/4
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