Question

Find the nature of roots of a quadratic equation X square - 4 x + 5 is equal to zero

Answer 1

Answer:

If a quadratic equation is ax^2+bx+c=0

Then,

D=b^2-4ac,is called the discriminant of the quadratic equation,

If D > 0, then, the quadratic equation has two distinct real roots,

If D < 0, then, the quadratic equation has two distinct imaginary roots,

If D = 0, then, the quadratic equation has two real equal roots,

Here, the given quadratic equation is,

x^2-4x+5=0

since,

(-4)^2-4*1*5=16-20=-4<0

Step-by-step explanation:

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Answer 2

If a quadratic equation is ax^2 + bx + c = 0 , then-

D = b^2 - 4ac is called the discriminant of the quadratic equation,

If D > 0, then, the quadratic equation has two distinct real roots,

If D < 0, then, the quadratic equation has two distinct imaginary roots,

If D = 0, then, the quadratic equation has two real equal roots,