Question

find the nature of roots of quadratic equation
...( x - √2)²-2(x+1)=0
Plz answer fast

Answer 1

here is your answer....

Answer 2

Hey !!!!

---- Here is your answer ---

I think its wrong then also....

( x - √2)2 - 2(x+1) = 0
Using the formula (a-b)2 = a2 +b2 -2ab

(x)2 + (√2)2 -2 (√2x) - 2x -2 = 0
x2 +2 -2√2x -2x -2 = 0
x2 -2√2x - 2x -2 = 0
x2 - (2√2 + 1)x -0

Then using b2 - 4ac


(-2√2 +1) 2 - 4
= 5

So two distinct real roots