find the nature of roots of the quadratic equation 3x²-4 root3 x+4=0
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Answer:
Step-by-step explanation:
here , let P(x) = 3x^2 + (4root3)x + 4 = 0
While comparing it with the general form of quadratic equation we get,
a = 3
b = (4root3)
c = 4
As
D = b^2 - 4ac
D = (4root3)(4root3) - 4(3)(4)
D = 16*3 - 12*4
D = 48 - 48
D = 0
HERE , as D=0
therefore , the nature of roots of P(x) will be real and equal
HOPE IT HAS SATISFIED YOU
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