Math, asked by orangelimesoda, 6 months ago

find the nature of roots of the quadratic equation 3x²-4 root3 x+4=0​

Answers

Answered by kushsingh2331
2

Answer:

Step-by-step explanation:

here , let P(x) = 3x^2 + (4root3)x + 4 = 0

While comparing it with the general form of quadratic equation we get,

a = 3

b = (4root3)

c = 4

As

D = b^2 - 4ac

    D =  (4root3)(4root3) - 4(3)(4)

        D = 16*3 - 12*4

D = 48 - 48

D = 0

HERE , as D=0

therefore , the nature of roots of P(x) will be real and equal

HOPE IT HAS SATISFIED YOU  

Similar questions
Math, 10 months ago