Question

find the nature of roots of the quardratic equation

$4x2 + 4 \sqrt{3 } x + 3 = 0$

Answer 1

Answer:0

b^{2} -4ac

(4\sqrt{3x } )^{2}-4(4)(3)

48-48=0

the roots are real and equal

Answer 2

Heya

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4x² + 2√3x + 2√3x + 3 = 0

=>

2x ( 2x + √3 ) + √3 ( 2x + 3/√3 ) = 0

=>

( 2x + √3 ) = 0

OR

( 2x + √3 ) =0

=>

2x = -√3

=>

x = -√3/2 OR x = -√3/2

So, The nature of roots are real and equal.

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A/√A = √A

3/√3 = √3