Question

the sum of a natural number and its square is 42 find the numbers

Answer 1

HELL DEAR FRIEND

LET THE NUMBER BE X

ATQ,

X² + X = 42

X² + X - 42 = 0

X² + 7X - 6X - 42 = 0

X(X + 7) -6(X + 7)

(X - 6)(X + 7)

X = 6 , -7

SINCE IT'S A NATURAL NUMBER SO

$\huge \boxed{X=6 }$

THANKS

HOPE IT HELPS YOU DEAR FRIEND

Answer 2

Step-by-step explanation:

HELL DEAR FRIEND

LET THE NUMBER BE X

ATQ,

X² + X = 42

X² + X - 42 = 0

X² + 7X - 6X - 42 = 0

X(X + 7) -6(X + 7)

(X - 6)(X + 7)

X = 6 , -7

SINCE IT'S A NATURAL NUMBER SO

\huge \boxed{X=6 }

X=6

THANKS

HOPE IT HELPS YOU DEAR FRIEND