Question

find the nature of roots of x square - x - 2 =0​

Answer 1

Step-by-step explanation:

Given that, 

x²-x−2=0

Comparing with ax²+bx+c=0, we get,

a=1,b=−1 and c=−2

We know that, D=b2−4ac

∴ D=(−1)²−4(1)(−2)=1+8=9

⇒D>0

Since, the discriminant is positive, the given equation will have two distinct real roots.

Answer 2

Answer:

Step-by-step explanation:

x2 – x + 2 = 0 Compare given equation with the general form of quadratic equation, which is ax2 + bx + c = 0 a = 1, b = – 1, c = 2 Discriminant: D = b2 – 4ac = (– 1)2 – 4 x 1 x 2 = 1 – 8 = – 7 < 0 Equation has no real roots.Read more on Sarthaks.com - https://www.sarthaks.com/704474/find-the-nature-of-the-roots-of-thequadratic-equation-x-2-x-2-0