Question

find the nature of roots
$2{x}^{2} + 2 \sqrt{3x } + 5 = 0$
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Answer 1

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Answer 2

Step-by-step explanation:

$b {}^{2} - 4ac =( 2 \sqrt{3} ) {}^{2} - 4 \times 2 \times 5 \\ = 12 - 40 \\ = - 28$

since, b2-4ac is less than 0.

therefore roots are not real.

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